Identify the compound which can show geometri | vedclass

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Question

(B) For a compound to show geometrical isomerism,it must have restricted rotation and the groups attached to the atoms involved in the restricted rota

Vedclass · Accepted Answer

$2$,$2$'-dibromo-$6$,$6$'-dichlorobiphenyl

Vedclass · Answer

(B) For a compound to show geometrical isomerism,it must have restricted rotation and the groups attached to the atoms involved in the restricted rotation must be different.$A$. $3$-methylcyclopentylidene: The exocyclic double bond has two identical hydrogen atoms on the terminal carbon,so it cannot show geometrical isomerism.$B$. $2,2'$-dibromo-$6,6'$-dichlorobiphenyl: This is a substituted biphenyl. Due to the bulky groups at the ortho positions ($Br$ and $Cl$),there is restricted rotation around the single bond connecting the two phenyl rings (atropisomerism). Since each ring has different groups at the ortho positions,it can show geometrical isomerism (specifically,it exists as enantiomeric atropisomers).$C$. $1,1'$-bicyclopropyl: This molecule has free rotation around the single bond connecting the two cyclopropyl rings,so it does not show geometrical isomerism.$D$. Decalin: This is a bicyclic system that exists as cis and trans isomers,but the question typically refers to alkene-type or restricted rotation systems. However,among the given options,$B$ is the classic example of restricted rotation leading to isomerism.

Identify the compound which can show geometrical isomerism:

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